6x^(2/3)-41x^(1/3)-7=0

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Solution for 6x^(2/3)-41x^(1/3)-7=0 equation: 


x in (-oo:+oo)

6*x^(2/3)-(41*x^(1/3))-7 = 0

6*x^(2/3)-41*x^(1/3)-7 = 0

t_1 = x^(1/3)

6*t_1^2-41*t_1^1-7 = 0

6*t_1^2-41*t_1-7 = 0

DELTA = (-41)^2-(-7*4*6)

DELTA = 1849

DELTA > 0

t_1 = (1849^(1/2)+41)/(2*6) or t_1 = (41-1849^(1/2))/(2*6)

t_1 = 7 or t_1 = -1/6

t_1 = -1/6

x^(1/3)+1/6 = 0

1*x^(1/3) = -1/6 // : 1

x^(1/3) = -1/6

( -1/6 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 7

x^(1/3)-7 = 0

1*x^(1/3) = 7 // : 1

x^(1/3) = 7

x^(1/3) = 7 // ^ 3

x = 343

x = 343

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